DevelopPHP
home Forum gear home

Libraries book

HTML Library CSS Library JavaScript Library PHP Library

Videosbook

PHP and MySQL JavaScript HTML and CSS Vector and 3D Flash Actionscript Android Dev Miscellaneous

Resourcesbook

Website Hosting
<iframe width="560" height="315" src="http://www.youtube.com/embed/woNQ2MA_0XU" frameborder="0" allowfullscreen></iframe>
You can embed this video on your blog or web page by copying the video embed code above and pasting it into the source code of your page. Adjust the width and height to specify the size you would like it to display.
Thumb Ajax Post to PHP File XMLHttpRequest Object Return Data Javascript Tutorial
Embed Source - http://www.youtube.com/watch?v=woNQ2MA_0XU
Publish Date - Jul 16, 2011     Author - Adam Khoury
Ajax Post to PHP File XMLHttpRequest Object Return Data Javascript Tutorial
Learn to program the javascript XMLHttpRequest Object to easily send Ajax HTTP requests to your PHP parsing scripts, and get return data from submitted forms or any type of interaction that takes place on your website. We establish the request object and simply access the events, methods, and properties we need for two way Javascript and PHP communication.
Lesson Code
<!-- THE PHP SCRIPT NAMED my_parse_file.php -->

<?php 
echo 'Thank you '. $_POST['firstname'] . ' ' . $_POST['lastname'] . ', says the PHP file';
?>

<!-- THE HTML PAGE AND JAVASCRIPT -->

<html>
<head>
<script language="JavaScript" type="text/javascript">
function ajax_post(){
    // Create our XMLHttpRequest object
    var hr = new XMLHttpRequest();
    // Create some variables we need to send to our PHP file
    var url = "my_parse_file.php";
    var fn = document.getElementById("first_name").value;
    var ln = document.getElementById("last_name").value;
    var vars = "firstname="+fn+"&lastname="+ln;
    hr.open("POST", url, true);
    // Set content type header information for sending url encoded variables in the request
    hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    // Access the onreadystatechange event for the XMLHttpRequest object
    hr.onreadystatechange = function() {
   if(hr.readyState == 4 && hr.status == 200) {
   var return_data = hr.responseText;
document.getElementById("status").innerHTML = return_data;
   }
    }
    // Send the data to PHP now... and wait for response to update the status div
    hr.send(vars); // Actually execute the request
    document.getElementById("status").innerHTML = "processing...";
}
</script>
</head>
<body>
<h2>Ajax Post to PHP and Get Return Data</h2>
Your First Name: <input id="first_name" name="first_name" type="text" /> 
<br /><br />
Your Last Name: <input id="last_name" name="last_name" type="text" />
<br /><br />
<input name="myBtn" type="submit" value="Submit Data" onClick="javascript:ajax_post();">
<br /><br />
<div id="status"></div>
</body>
</html>

Home   •   Terms of Use   •   Developer Forums   •   T-Shirts   •   RSS   •   Classroom Chalkboard   •   Donate   •   Top ↑
Popular In PHP / MySQL E-Commerce Store Production
Social Network Website Building
Image Upload / Photo Processing
CMS Software Programming
Mass Email Systems
Magic XML Data
Search Programming
Popular In JavaScript JSON Programming
Ajax Programming
Animating Elements
WYSIWYG Programming
Date/Time Programming
DOM Scripting
Object Reference
Popular In HTML Canvas Element
New Form Elements
Audio Element
Video Element
Drag and Drop
Event Handling
Element Grouping
Popular In CSS Custom Font Embedding
Dynamic Fit Backgrounds
Theatre Mode
Box Overlays
CSS Level 1 Properties
CSS Level 2 Properties
CSS Level 3 Properties
©2013 DevelopPHP   |   Navigate to related domains HTML5